Q1. Find the simple interest on ₹5000 at 5% per annum for 4 years (in ₹).
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Answer: C. 1000
SI = 5000 × 5 × 4 / 100 = ₹1000.
Simple Interest Questions for SSC CGL (with Answers)
43 Simple Interest MCQs from the Quantitative Aptitude section, with answers and short explanations.
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Q2. Find the simple interest on ₹1000 at 5% per annum for 5 years (in ₹).
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Answer: A. 250
SI = 1000 × 5 × 5 / 100 = ₹250.
Q3. Find the simple interest on ₹15500 at 8% per annum for 5 years (in ₹).
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Answer: A. 6200
SI = 15500 × 8 × 5 / 100 = ₹6200.
Q4. Find the simple interest on ₹14000 at 12% per annum for 4 years (in ₹).
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Answer: C. 6720
SI = 14000 × 12 × 4 / 100 = ₹6720.
Q5. Find the simple interest on ₹18500 at 8% per annum for 2 years (in ₹).
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Answer: A. 2960
SI = 18500 × 8 × 2 / 100 = ₹2960.
Q6. Find the simple interest on ₹12000 at 6% per annum for 2 years (in ₹).
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Answer: C. 1440
SI = 12000 × 6 × 2 / 100 = ₹1440.
Q7. Find the simple interest on ₹17000 at 10% per annum for 3 years (in ₹).
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Answer: A. 5100
SI = 17000 × 10 × 3 / 100 = ₹5100.
Q8. Find the simple interest on ₹4000 at 10% per annum for 2 years (in ₹).
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Answer: D. 800
SI = 4000 × 10 × 2 / 100 = ₹800.
Q9. Find the simple interest on ₹5500 at 12% per annum for 5 years (in ₹).
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Answer: D. 3300
SI = 5500 × 12 × 5 / 100 = ₹3300.
Q10. Find the simple interest on ₹3000 at 8% per annum for 4 years (in ₹).
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Answer: D. 960
SI = 3000 × 8 × 4 / 100 = ₹960.
Q11. Find the simple interest on ₹3000 at 10% per annum for 5 years (in ₹).
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Answer: A. 1500
SI = 3000 × 10 × 5 / 100 = ₹1500.
Q12. At 5% per annum simple interest, a sum earns ₹2400 as interest in 3 years. Find the sum (in ₹).
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Answer: D. 16000
P = 2400 × 100 / (5 × 3) = ₹16000.
Q13. Find the simple interest on ₹3000 at 15% per annum for 3 years (in ₹).
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Answer: A. 1350
SI = 3000 × 15 × 3 / 100 = ₹1350.
Q14. At 5% per annum simple interest, a sum earns ₹2000 as interest in 5 years. Find the sum (in ₹).
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Answer: B. 8000
P = 2000 × 100 / (5 × 5) = ₹8000.
Q15. Find the simple interest on ₹20000 at 5% per annum for 2 years (in ₹).
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Answer: C. 2000
SI = 20000 × 5 × 2 / 100 = ₹2000.
Q16. At 6% per annum simple interest, a sum earns ₹2880 as interest in 4 years. Find the sum (in ₹).
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Answer: C. 12000
P = 2880 × 100 / (6 × 4) = ₹12000.
Q17. Find the simple interest on ₹18000 at 15% per annum for 4 years (in ₹).
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Answer: C. 10800
SI = 18000 × 15 × 4 / 100 = ₹10800.
Q18. At 12% per annum simple interest, a sum earns ₹3900 as interest in 5 years. Find the sum (in ₹).
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Answer: B. 6500
P = 3900 × 100 / (12 × 5) = ₹6500.
Q19. Find the simple interest on ₹1000 at 4% per annum for 5 years (in ₹).
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Answer: B. 200
SI = 1000 × 4 × 5 / 100 = ₹200.
Q20. Find the simple interest on ₹4000 at 6% per annum for 5 years (in ₹).
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Answer: B. 1200
SI = 4000 × 6 × 5 / 100 = ₹1200.
Q21. A sum of ₹2500 amounts to ₹3625 in 3 years at simple interest. What is the rate of interest per annum?
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Answer: C. 15%
SI = 3625 − 2500 = ₹1125. R = 1125 × 100 / (2500 × 3) = 15%.
Q22. A sum of ₹17000 amounts to ₹29750 in 5 years at simple interest. What is the rate of interest per annum?
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Answer: B. 15%
SI = 29750 − 17000 = ₹12750. R = 12750 × 100 / (17000 × 5) = 15%.
Q23. A sum of ₹3500 amounts to ₹3780 in 2 years at simple interest. What is the rate of interest per annum?
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Answer: A. 4%
SI = 3780 − 3500 = ₹280. R = 280 × 100 / (3500 × 2) = 4%.
Q24. A sum of ₹4500 amounts to ₹5400 in 4 years at simple interest. What is the rate of interest per annum?
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Answer: A. 5%
SI = 5400 − 4500 = ₹900. R = 900 × 100 / (4500 × 4) = 5%.
Q25. A sum of ₹9500 amounts to ₹12540 in 4 years at simple interest. What is the rate of interest per annum?
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Answer: B. 8%
SI = 12540 − 9500 = ₹3040. R = 3040 × 100 / (9500 × 4) = 8%.
Q26. A sum of ₹8500 amounts to ₹14875 in 5 years at simple interest. What is the rate of interest per annum?
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Answer: A. 15%
SI = 14875 − 8500 = ₹6375. R = 6375 × 100 / (8500 × 5) = 15%.
Q27. A sum of ₹16500 amounts to ₹20625 in 5 years at simple interest. What is the rate of interest per annum?
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Answer: B. 5%
SI = 20625 − 16500 = ₹4125. R = 4125 × 100 / (16500 × 5) = 5%.
Q28. A sum of ₹11000 amounts to ₹11880 in 2 years at simple interest. What is the rate of interest per annum?
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Answer: B. 4%
SI = 11880 − 11000 = ₹880. R = 880 × 100 / (11000 × 2) = 4%.
Q29. At 8% per annum simple interest, a sum earns ₹1400 as interest in 5 years. Find the sum (in ₹).
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Answer: B. 3500
P = 1400 × 100 / (8 × 5) = ₹3500.
Q30. A sum of ₹3000 amounts to ₹4800 in 5 years at simple interest. What is the rate of interest per annum?
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Answer: B. 12%
SI = 4800 − 3000 = ₹1800. R = 1800 × 100 / (3000 × 5) = 12%.
Q31. At 12% per annum simple interest, a sum earns ₹1200 as interest in 2 years. Find the sum (in ₹).
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Answer: B. 5000
P = 1200 × 100 / (12 × 2) = ₹5000.
Q32. A sum of ₹13500 amounts to ₹15120 in 2 years at simple interest. What is the rate of interest per annum?
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Answer: C. 6%
SI = 15120 − 13500 = ₹1620. R = 1620 × 100 / (13500 × 2) = 6%.
Q33. At 12% per annum simple interest, a sum earns ₹1260 as interest in 3 years. Find the sum (in ₹).
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Answer: A. 3500
P = 1260 × 100 / (12 × 3) = ₹3500.
Q34. At 5% per annum simple interest, a sum earns ₹1750 as interest in 5 years. Find the sum (in ₹).
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Answer: C. 7000
P = 1750 × 100 / (5 × 5) = ₹7000.
Q35. At 10% per annum simple interest, a sum earns ₹9250 as interest in 5 years. Find the sum (in ₹).
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Answer: D. 18500
P = 9250 × 100 / (10 × 5) = ₹18500.
Q36. A sum of ₹16000 amounts to ₹20800 in 3 years at simple interest. What is the rate of interest per annum?
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Answer: D. 10%
SI = 20800 − 16000 = ₹4800. R = 4800 × 100 / (16000 × 3) = 10%.
Q37. In how many years will a sum of money become three times itself at 8% per annum simple interest?
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Answer: A. 25 years
SI = 2P, so 2P = P × 8 × T / 100, giving T = 200/8 = 25 years.
Q38. In how many years will a sum of money become double itself at 5% per annum simple interest?
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Answer: B. 20 years
SI = 1P, so 1P = P × 5 × T / 100, giving T = 100/5 = 20 years.
Q39. In how many years will a sum of money become four times itself at 5% per annum simple interest?
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Answer: A. 60 years
SI = 3P, so 3P = P × 5 × T / 100, giving T = 300/5 = 60 years.
Q40. In how many years will a sum of money become four times itself at 15% per annum simple interest?
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Answer: C. 20 years
SI = 3P, so 3P = P × 15 × T / 100, giving T = 300/15 = 20 years.
Q41. In how many years will a sum of money become double itself at 10% per annum simple interest?
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Answer: C. 10 years
SI = 1P, so 1P = P × 10 × T / 100, giving T = 100/10 = 10 years.
Q42. In how many years will a sum of money become double itself at 4% per annum simple interest?
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Answer: A. 25 years
SI = 1P, so 1P = P × 4 × T / 100, giving T = 100/4 = 25 years.
Q43. In how many years will a sum of money become three times itself at 5% per annum simple interest?
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Answer: C. 40 years
SI = 2P, so 2P = P × 5 × T / 100, giving T = 200/5 = 40 years.
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