Q1. A trader marks an article at ₹2000 and allows a discount of 25%. He still earns a profit of 50%. What is the cost price of the article (in ₹)?
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Answer: B. 1000
SP = 2000 × 75/100 = ₹1500. CP = 1500 × 100/150 = ₹1000.
SSC CGL Quantitative Aptitude Advanced Practice Set 5
25 advanced questions, suggested time 30 minutes. Tap an option to check it, or open “Show answer” for the explanation.
Topics: Profit and Loss, Simple Interest, Compound Interest, Average, Ratio and Proportion, Pipes and Cisterns, Speed, Time and Distance, LCM and HCF, Number System, Algebra, Problems on Ages, Mensuration, Partnership, Discount, Trigonometry
Score: 0 / 0
Q2. In how many years will a sum of money become four times itself at 15% per annum simple interest?
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Answer: C. 20 years
SI = 3P, so 3P = P × 15 × T / 100, giving T = 300/15 = 20 years.
Q3. What is the difference between compound interest and simple interest on ₹22000 for 2 years at 10% per annum (in ₹)?
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Answer: C. 220
CI − SI = 22000 × (10/100)² = ₹220.
Q4. The average of 11 consecutive even numbers is 112. What is the largest of these numbers?
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Answer: A. 122
The middle (6th) number is 112. The largest is 5 steps of 2 above it: 112 + 10 = 122.
Q5. Find the mean proportional between 320 and 200.
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Answer: A. 40
√(320 × 200) = √64000 = 40.
Q6. A pipe can fill a tank in 36 hours, while a leak can empty the full tank in 45 hours. If both are open, how long will it take to fill the tank?
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Answer: A. 180 hours
Net filled per hour = 1/36 − 1/45 = 9/1620. Time = 1620/9 = 180 hours.
Q7. A man travels from A to B at 12 km/h and returns at 36 km/h. What is his average speed for the whole journey?
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Answer: C. 18 km/h
Average speed = 2 × 12 × 36/(12 + 36) = 18 km/h.
Q8. The HCF of two numbers is 22 and their LCM is 462. If one of the numbers is 154, find the other.
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Answer: A. 66
Other number = (22 × 462) / 154 = 66.
Q9. What is the remainder when 1103 is divided by 9?
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Answer: B. 5
1103 = 9 × 122 + 5. Remainder = 5.
Q10. If x + 1/x = 8, find the value of x² + 1/x².
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Answer: B. 62
x² + 1/x² = 8² − 2 = 62.
Q11. A father is 4 times as old as his son. If the son is 5 years old, what will the father's age be after 5 years?
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Answer: D. 25 years
Father's present age = 4 × 5 = 20. After 5 years: 25 years.
Q12. Find the volume of a cylinder with radius 7 cm and height 11 cm. (Take π = 22/7)
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Answer: D. 1694 cm³
V = 22/7 × 7² × 11 = 1694 cm³.
Q13. A invests ₹25000 for 12 months and B invests ₹30000 for 12 months. Out of a total profit of ₹10428, what is A's share (in ₹)?
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Answer: B. 4740
Ratio = 25000×12 : 30000×12 = 5:6. A's share = 10428 × 5/11 = ₹4740.
Q14. A trader marks an article at ₹2400 and allows a discount of 25%. He still earns a profit of 50%. What is the cost price of the article (in ₹)?
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Answer: D. 1200
SP = 2400 × 75/100 = ₹1800. CP = 1800 × 100/150 = ₹1200.
Q15. Two successive discounts of 20% and 5% are equivalent to a single discount of:
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Answer: B. 24%
Equivalent = 20 + 5 − (20×5)/100 = 24%.
Q16. In how many years will a sum of money become double itself at 10% per annum simple interest?
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Answer: C. 10 years
SI = 1P, so 1P = P × 10 × T / 100, giving T = 100/10 = 10 years.
Q17. The average of 9 consecutive even numbers is 62. What is the largest of these numbers?
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Answer: C. 70
The middle (5th) number is 62. The largest is 4 steps of 2 above it: 62 + 8 = 70.
Q18. Find the mean proportional between 72 and 192.
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Answer: A. 24
√(72 × 192) = √13824 = 24.
Q19. A pipe can fill a tank in 24 hours, while a leak can empty the full tank in 48 hours. If both are open, how long will it take to fill the tank?
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Answer: A. 48 hours
Net filled per hour = 1/24 − 1/48 = 24/1152. Time = 1152/24 = 48 hours.
Q20. The HCF of two numbers is 11 and their LCM is 154. If one of the numbers is 22, find the other.
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Answer: B. 77
Other number = (11 × 154) / 22 = 77.
Q21. What is the remainder when 9792 is divided by 11?
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Answer: C. 2
9792 = 11 × 890 + 2. Remainder = 2.
Q22. If x + 1/x = 9, find the value of x² + 1/x².
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Answer: A. 79
x² + 1/x² = 9² − 2 = 79.
Q23. A father is 3 times as old as his son. If the son is 12 years old, what will the father's age be after 10 years?
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Answer: D. 46 years
Father's present age = 3 × 12 = 36. After 10 years: 46 years.
Q24. Find the area of a triangle whose sides are 5 cm, 12 cm and 13 cm.
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Answer: A. 30 cm²
5² + 12² = 13², so it is right-angled. Area = ½ × 5 × 12 = 30 cm².
Q25. Find the value of tan 45° + sin 90°.
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Answer: C. 2
1 + 1 = 2.