SSC CGL Quantitative Aptitude Beginner Practice Set 8
25 beginner questions. Tap an option to check it, or open “Show answer” for the explanation.
Topics: Percentage, Speed, Time and Distance, Average, Profit and Loss, Time and Work, Simple Interest, Number System, Compound Interest, Simplification, Mensuration, Ratio and Proportion, Statistics, Geometry, LCM and HCF
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Q1. 128 is what percent of 320?
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Answer: D. 40%
128/320 × 100 = 40%.
Percentage · easy
Q2. Convert 99 km/h into m/s.
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Answer: C. 27.5 m/s
99 × 5/18 = 27.5 m/s.
Speed, Time and Distance · easy
Q3. What is 50% of 1740?
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Answer: D. 870
50% of 1740 = 50/100 × 1740 = 870.
Percentage · easy
Q4. What is the average of the first 17 even natural numbers?
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Answer: B. 18
Sum = 17 × 18 = 306; average = 18.
Average · easy
Q5. The cost price of 10 articles is equal to the selling price of 8 articles. Find the profit percentage.
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Answer: B. 25%
CP of 8 articles = ₹8; SP of 8 articles = ₹10. Profit% = (10 − 8)/8 × 100 = 25%.
Profit and Loss · medium
Q6. An article is bought for ₹500 and sold at a profit of 50%. What is the selling price (in ₹)?
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Answer: C. 750
SP = 500 × 150/100 = ₹750.
Profit and Loss · easy
Q7. 30 men can complete a work in 32 days. In how many days can 6 men complete the same work?
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Answer: C. 160 days
30 × 32 = 6 × D ⇒ D = 960/6 = 160 days.
Time and Work · easy
Q8. Convert 180 km/h into m/s.
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Answer: A. 50 m/s
180 × 5/18 = 50 m/s.
Speed, Time and Distance · easy
Q9. Convert 144 km/h into m/s.
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Answer: A. 40 m/s
144 × 5/18 = 40 m/s.
Speed, Time and Distance · easy
Q10. The cost price of 20 articles is equal to the selling price of 16 articles. Find the profit percentage.
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Answer: D. 25%
CP of 16 articles = ₹16; SP of 16 articles = ₹20. Profit% = (20 − 16)/16 × 100 = 25%.
Profit and Loss · medium
Q11. Find the simple interest on ₹3000 at 10% per annum for 5 years (in ₹).
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Answer: A. 1500
SI = 3000 × 10 × 5 / 100 = ₹1500.
Simple Interest · easy
Q12. What is the largest 3-digit number exactly divisible by 9?
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Answer: C. 999
999 ÷ 9 leaves remainder 0. 999 − 0 = 999.
Number System · medium
Q13. Find the compound interest on ₹6000 for 2 years at 5% per annum, compounded annually (in ₹).
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Answer: A. 615
Amount = 6000 × (105/100)² = ₹6615. CI = 6615 − 6000 = ₹615.
Compound Interest · easy
Q14. Simplify: 4/5 + 2/3
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Answer: C. 1 7/15
4/5 + 2/3 = 1 7/15.
Simplification · easy
Q15. Find the average of 96, 46, 94, 72.
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Answer: D. 77
Sum = 308; average = 308/4 = 77.
Average · easy
Q16. The perimeter of a square is 140 cm. Find its area.
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Answer: D. 1225 cm²
Side = 140/4 = 35 cm; area = 35² = 1225 cm².
Mensuration · easy
Q17. Convert 108 km/h into m/s.
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Answer: A. 30 m/s
108 × 5/18 = 30 m/s.
Speed, Time and Distance · easy
Q18. ₹160 is divided between A and B in the ratio 1:4. What is A's share (in ₹)?
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Answer: B. 32
A's share = 160 × 1/5 = ₹32.
Ratio and Proportion · easy
Q19. Find the median of: 31, 51, 26, 8, 6, 7, 23, 12.
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Answer: D. 17.5
In order: 6, 7, 8, 12, 23, 26, 31, 51. Median = 17.5.
Statistics · easy
Q20. The cost price of 25 articles is equal to the selling price of 20 articles. Find the profit percentage.
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Answer: B. 25%
CP of 20 articles = ₹20; SP of 20 articles = ₹25. Profit% = (25 − 20)/20 × 100 = 25%.
Profit and Loss · medium
Q21. In a right-angled triangle, the two sides containing the right angle are 24 cm and 70 cm. Find the hypotenuse.
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Answer: A. 74 cm
√(24² + 70²) = √5476 = 74 cm.
Geometry · easy
Q22. A cyclist covers 132 km in 4 hours. What is its average speed?
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Answer: C. 33 km/h
Speed = 132/4 = 33 km/h.
Speed, Time and Distance · easy
Q23. Find the value of 93² − 47².
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Answer: D. 6440
(93 + 47)(93 − 47) = 140 × 46 = 6440.
Simplification · medium
Q24. The cost price of 15 articles is equal to the selling price of 12 articles. Find the profit percentage.
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Answer: D. 25%
CP of 12 articles = ₹12; SP of 12 articles = ₹15. Profit% = (15 − 12)/12 × 100 = 25%.
Profit and Loss · medium
Q25. Find the HCF of 35 and 15.
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Answer: D. 5
35 = 5 × 7, 15 = 5 × 3. Since 7 and 3 share no factor, HCF = 5.
LCM and HCF · easy