SSC CGL MCQ Practice 2026

SSC CGL Quantitative Aptitude Beginner Practice Set 9

25 beginner questions. Tap an option to check it, or open “Show answer” for the explanation.

Topics: Simple Interest, Algebra, Boats and Streams, Speed, Time and Distance, Problems on Ages, Geometry, Profit and Loss, Mensuration, Percentage, Average, Simplification, Time and Work, Number System, Discount, Compound Interest

Score: 0 / 0

Q1. At 5% per annum simple interest, a sum earns ₹2400 as interest in 3 years. Find the sum (in ₹).

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Answer: D. 16000

P = 2400 × 100 / (5 × 3) = ₹16000.

Simple Interest · medium

Q2. If x + 9 = 13, find x.

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Answer: D. 4

1x = 13 − 9 = 4, so x = 4/1 = 4.

Algebra · easy

Q3. A boat goes downstream at 29 km/h and upstream at 17 km/h. What is the speed of the stream?

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Answer: D. 6 km/h

(29 − 17)/2 = 6 km/h.

Boats and Streams · medium

Q4. Convert 162 km/h into m/s.

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Answer: B. 45 m/s

162 × 5/18 = 45 m/s.

Speed, Time and Distance · easy

Q5. A father is 4 times as old as his son. If the son is 14 years old, what will the father's age be after 8 years?

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Answer: B. 64 years

Father's present age = 4 × 14 = 56. After 8 years: 64 years.

Problems on Ages · easy

Q6. How many diagonals does a polygon with 10 sides have?

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Answer: A. 35

10 × 7/2 = 35.

Geometry · medium

Q7. The cost price of 16 articles is equal to the selling price of 12 articles. Find the profit percentage.

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Answer: B. 33 1/3%

CP of 12 articles = ₹12; SP of 12 articles = ₹16. Profit% = (16 − 12)/12 × 100 = 33 1/3%.

Profit and Loss · medium

Q8. Find the area of a rectangle with length 23 m and breadth 6 m.

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Answer: D. 138 m²

Area = 23 × 6 = 138 m².

Mensuration · easy

Q9. 50 is what percent of 200?

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Answer: D. 25%

50/200 × 100 = 25%.

Percentage · easy

Q10. Two angles of a triangle are 30° and 73°. Find the third angle.

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Answer: B. 77°

Third angle = 180 − 30 − 73 = 77°.

Geometry · easy

Q11. What is the average of the first 19 even natural numbers?

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Answer: B. 20

Sum = 19 × 20 = 380; average = 20.

Average · easy

Q12. The cost price of 11 articles is equal to the selling price of 10 articles. Find the profit percentage.

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Answer: C. 10%

CP of 10 articles = ₹10; SP of 10 articles = ₹11. Profit% = (11 − 10)/10 × 100 = 10%.

Profit and Loss · medium

Q13. Simplify: 45 + 12 × 3 − 48

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Answer: C. 33

12 × 3 = 36; 45 + 36 − 48 = 33.

Simplification · easy

Q14. 19 men can complete a work in 30 days. In how many days can 15 men complete the same work?

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Answer: C. 38 days

19 × 30 = 15 × D ⇒ D = 570/15 = 38 days.

Time and Work · easy

Q15. Convert 126 km/h into m/s.

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Answer: D. 35 m/s

126 × 5/18 = 35 m/s.

Speed, Time and Distance · easy

Q16. What is 15% of 1860?

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Answer: A. 279

15% of 1860 = 15/100 × 1860 = 279.

Percentage · easy

Q17. The cost price of 12 articles is equal to the selling price of 10 articles. Find the profit percentage.

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Answer: C. 20%

CP of 10 articles = ₹10; SP of 10 articles = ₹12. Profit% = (12 − 10)/10 × 100 = 20%.

Profit and Loss · medium

Q18. What is the smallest 3-digit number exactly divisible by 13?

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Answer: C. 104

100 ÷ 13 leaves remainder 9. 100 + 4 = 104.

Number System · medium

Q19. The marked price of a shirt is ₹4500. A discount of 20% is given. What is the selling price (in ₹)?

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Answer: B. 3600

SP = 4500 × 80/100 = ₹3600.

Discount · easy

Q20. Simplify: 1/2 + 5/3

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Answer: D. 2 1/6

1/2 + 5/3 = 2 1/6.

Simplification · easy

Q21. The cost price of 20 articles is equal to the selling price of 15 articles. Find the profit percentage.

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Answer: A. 33 1/3%

CP of 15 articles = ₹15; SP of 15 articles = ₹20. Profit% = (20 − 15)/15 × 100 = 33 1/3%.

Profit and Loss · medium

Q22. Find the simple interest on ₹3000 at 15% per annum for 3 years (in ₹).

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Answer: A. 1350

SI = 3000 × 15 × 3 / 100 = ₹1350.

Simple Interest · easy

Q23. The diagonal of a square is 37√2 cm. Find its area.

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Answer: B. 1369 cm²

Side = 37 cm, so area = 1369 cm².

Mensuration · medium

Q24. Convert 45 km/h into m/s.

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Answer: C. 12.5 m/s

45 × 5/18 = 12.5 m/s.

Speed, Time and Distance · easy

Q25. Find the compound interest on ₹10000 for 2 years at 20% per annum, compounded annually (in ₹).

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Answer: D. 4400

Amount = 10000 × (120/100)² = ₹14400. CI = 14400 − 10000 = ₹4400.

Compound Interest · easy